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Tresset [83]
3 years ago
11

-GEOMETRY PROBLEM- I don’t understand this problem, can anybody help? The question is in the picture. Thanks! I’ll give 15 point

s!

Mathematics
1 answer:
svetoff [14.1K]3 years ago
3 0
In tue picture, we can see 2 triangles and they already labeled 2 congruent sides. We also see that the line in the middle is being shared between the 2 triangles, making the side equal. Using the SSS theorem, we can prove that these teiangles are congruent to each other. Hope this helps.
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Expand, simplify qu. 10 to 18..... :- / Lots of points easy read attachment
Vinvika [58]

Step-by-step explanation:

10. 8a - 12b

11. d^8

12. 3y^3

13. 4a+b

14. 11x-3

15. 2a^2+2ab

16. 2x^3+x

17. 4(a+2)

18. 3m(m-3)

8 0
3 years ago
Please show work pls!!!
antoniya [11.8K]

this property name is multiplicative inverse

3 0
2 years ago
What is the GCF of 525, 135, 750
Ede4ka [16]

Answer:

75.

Step-by-step explanation:

The GCF, or Greatest Common Factor, of 525, 135, and 750 is 75, and how we know this is to do some simple math.

Take all the numbers, simply factor each value first and then we choose all the copies of factors and multiply them.

6 0
2 years ago
Question is 15 points
mihalych1998 [28]

This is a doozy so pay attention. First thing you have to recognize is that is a trig identity, the sum identity for cosine to be exact. That formula is

cos(\alpha +\beta )=cos\alpha cos\beta -sin\alpha sin\beta.

So that means you need to find the cosine of alpha and the sin of beta. We are given the sin of alpha being 4/5 in the first quadrant. If you set up the sin ratio which is side opposite over hypotenuse of a right triangle, you put the 4 on the side opposite the reference angle, alpha, and the hypotenuse of 5 on the terminal ray and then you have to find the missing side of the right triangle you created. Using Pythagorean's theorem, you find that the missing side, which is the adjacent side to alpha, is 3. Now you can find the cosine of alpha as well, since cosine is the side adjacent, 3, over the hypotenuse, 5. So far wwe have

sin\alpha =\frac{4}{5} and

cos\alpha =\frac{3}{5} for that first angle. Now moving on to the second angle. The cosine of beta is side adjacent, 5, over the hypotenuse, 13, and we are missing the side opposite the reference angle beta. Using Pythagorean's theorem again to find the side opposite, we have that that side measures 12. Now we can find the sine of beta using that opposite side, 12, over the hypotenuse, 13. What we have now is

cos\beta =\frac{5}{13} and

sin\beta =\frac{12}{13}. According to the identity, we have to multiply those ratios now:

(\frac{3}{5}*\frac{5}{13})-(\frac{4}{5}*\frac{12}{13}).

When you do that you get

\frac{3}{13}-\frac{48}{65}.

Of course in order to subtract those 2 fractions you need a common denominator which is 65 so

\frac{15}{65}-\frac{48}{65} which gives you a final answer of -\frac{33}{65} which is the first choice given above. There you go!

4 0
3 years ago
The logarithm of the base to it self is always......​
Elanso [62]

Answer:

Step-by-step explanation:

Logₐa = 1

6 0
3 years ago
Read 2 more answers
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