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2 years ago

Mitch is attending a 4-year college. As a freshman, he was approved for a 10-year, federal

Mathematics

1 answer:

stich3 [128]2 years ago

6 0

Answer:

Interest capitalization occurs when unpaid interest is added to the principal amount of your student loan. When the interest on your federal student loan is not paid as it accrues (during periods when you are responsible for paying the interest), your lender may capitalize the unpaid interest.

Step-by-step explanation:

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The triangle below has an area of 75 units squared. Find the missing side.

Volgvan

Answer:

x = 15 units

Step-by-step explanation:

Here, base of triangle = x units & height = 19 units

$Area( \triangle) = \frac{1}{2} \times base \times height \\ \\ 75 = \frac{1}{2} \times x \times 10 \\ \\ 75 = x \times 5 \\ \\ x = \frac{75}{5} \\ \\ \huge \purple{ \boxed{ x = 15 \: units}}$

5 0

3 years ago

Please please help me please help please please help me please help please

AVprozaik [17]

Answer:

Perimeter is 17.07

Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

We need to use the Pythagorean theorem to get the length of DE.

$DE = \sqrt{5^{2} +5^{2}}=\sqrt{50} = 7.07\\$

So the perimeter of DEF is 5 + 5 + 7.07 = 17.07

5 0

3 years ago

9x^2-6x+8=0 what is the fifth step in solving this equation

Simora [160]

Answer:

write the equation as a binomial

Step-by-step explanation:

8 0

3 years ago

Below are two different functions, f(x) and g(x). What can be determined about their y-intercepts? F(x)=-2x-1

katrin [286]

The function g(x) has a higher y intercept

3 0

3 years ago

Read 2 more answers

Use the Law of Sines to find the measure of angle J to the nearest degree.

rjkz [21]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$

8 0

3 years ago