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2 years ago

Brainliest to best answer

Mathematics

1 answer:

Veronika [31]2 years ago

8 0

Answer:

B. 3x -7y < -21

Step-by-step explanation:

For this problem, a quick way to the correct answer choice is to determine on which side of the y-intercept the equation tells you the solution lies. That is ...

set x=0
divide by the coefficient of y

Doing this transforms the answer choices to ...

A: y < 3

B: y > 3

C: y > -3

D: y < -3

The graph clearly shows the solution space on the y-axis is in the region y > 3, matching choice B.

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Find the value of x (click photo)

Zolol [24]

Answer:

x = 130 degrees

Step-by-step explanation:

7-sided polygon = 900 degrees

114 + 138 + 127 + 108 + 142 + 141 + x = 900

770 + x = 900

-770 -770

x = 130

Hope this helped! Have a nice day! Plz mark as brainliest!!!

-XxDeathshotxX

5 0

2 years ago

Read 2 more answers

Ok so do I subtract 5 from x and 5 Orr am I solving wrong i don’t know this is confusing.

Aleksandr [31]

Answer:

no you dont

Step-by-step explanation:

4 0

2 years ago

If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used: