Year Net Profit
1 <span>$14,250.00
2 $15,390.00
3 $16,621.20
4 $17,950.90</span>2
We need to get the increase of the net profit of the current year from the previous year.
Percentage increase = (Current year - Previous Year)/ Previous Year * 100%
Year 2: (15,390 - 14, 250) / 14,250 * 100% = 0.08 * 100% = 8%
Year 3: (16,621.20 - 15,390) / 15,390 * 100% = 0.08 * 100% = 8%
Year 4: (17,950.90 - 16,621.20) / 16,621.20 * 100% = 0.08 * 100% = 8%
Every year the net income increases by 8%. So, the net income in Year 5 will be:
17,950.90 x 1.08 = 19,386.97 Choice D.
Since ZY bisects GE and XY bisects EF, and both ZY and XY both bisect GF, then XY ~ ZE and ZY ~ XE.
Therefore ZE = XY = 5
And GE = 2× ZE (because bisected segments are = and therefore ×2 = long segment).
So GE = 2ZE = 2×5 = 10
Answer:
-15/2 or -7.5 or -7½
Negative StartFraction 15 Over 2 EndFraction
Step-by-step explanation:
Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.
Therefore;
M=∆y÷∆x
The change in y co-ordinates is given by
∆y=y2-y1
Similarly, change in x co-ordinates is given by
∆x=x2-x1
Given the two points as (5, 80) and (7, 65)
X1=5 Y1=80
X2=7 Y2=65
∆y=65-80=-15
∆x=7-5=2
Hence ∆y÷∆x will be -15÷2=-7.5 or -7½
Negative StartFraction 15 Over 2 EndFraction
Answer:
<em><u>Yes I Agree And Wanna Zoom?</u></em>
Answer: Option 'B' is correct.
Step-by-step explanation:
Let the initial concentration be

Let concentration after t= 90 hours be N
Since we have given that Sodium-24 has a half life of 15 hours i.e.

So, According to question,

As we know that

Hence, Option 'B' is correct.