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saveliy_v [14]
4 years ago
10

Four-fifths of my current age is greater than three-quarters of my age one year from now.

Mathematics
1 answer:
klasskru [66]4 years ago
8 0
Let current age be x, next we construct the inequalities for the age:
<span>Four-fifths of my current age is greater than three-quarters of my age one year from now.
</span>thus when we add 1 year to 3/4 of our current age and set the inequality
4x/5>3x/4+1......i

<span>Four-fifths of my current age is also greater than five-sixths of my age one year ago.
Thus when we subtract 1 from 5x/6 and set the inequality we get
4x/5>5x/6-1.......ii
solving the inequalities we obtain:
</span>4x/5>3x/4+1
x/20>1
hence multiplying both sides by 20 we obtain:
x>20

also

4x/5>5x/6-1
4x/5-5x/5>-1
-x/30>-1
multiplying both sides by 30 we get:
-x>-30
thus
x<30
therefore the possible values of my age will lie in the interval:
20<x<30
Thus our age is in the interval
(20,30)

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anzhelika [568]

Answer:

{-1, 5} (two real solutions).

Step-by-step explanation:

On the left side we want x^2, not x?

We need to rewrite x? = 4x - 5 in standard form, that is, as a quadratic with x terms in decreasing powers of x:

x^2 - 4x + 5 = 0

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4 0
3 years ago
During the World Series the host Citywide Hotel a occupancy Rose 21% over the prior busiest night if the busiest night had been
Natalka [10]

Answer:

The new record was 91.96%.

Step-by-step explanation:

As per the given statement: During the World Series the host Citywide Hotel a occupancy Rose 21% over the prior busiest night if the busiest night had been 76% occupancy.

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We will find the 21% of 76% and then added it to 76%.

\text{New record} = \text{old record} + \text{Increase in record}

New record = 76\% +(21\% \times 76\%)

New record = \frac{76}{100} +(\frac{21}{100}\times \frac{76}{100})

New record = 0.76 + (0.21 \times 0.76) = 0.76 + 0.159 = 09196

Convert this decimal number into percentage by just multiplying a number by 100 we get;

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4 0
3 years ago
What is the GCF of 54 and 33?
qaws [65]
54= 3*18
54= 3*3*6
54= 3*3*3*2

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The only shared factor is 3.
Final answer: 3
8 0
3 years ago
Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)
Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)=\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)=\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}

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3 years ago
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