Plug 6 for x.
f(6) = 6^2 / 3 + 6
f(6) = 36 / 3 + 6
f(6) = 12 + 6
f(6) = 18
Answer:
are zeroes of given quadratic equation.
Step-by-step explanation:
We have been a quadratic equation:
We need to find the zeroes of quadratic equation
We have a formula to find zeroes of a quadratic equation:
General form of quadratic equation is 
On comparing general equation with b given equation we get
a=2,b=-10,c=-3
On substituting the values in formula we get
Now substituting D in 
we get
Therefore,
So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.
Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4
So then we get 8x^4/(x^(3/4)+7x)^4
8x^4/(x^(3/4)+7x)^4
To the nearest foot, it would be 23 feet. I found this using the Pythagorean Theorem of a (squared) + b (squared) = c (squared). If you have 24 as the hypotenuse, you have to square this and subtract 64 (8*8) from it. That will equal 512. So you have to find the square root of that which is 22.62, which will round to 23 feet.
