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galina1969 [7]
3 years ago
7

Question: Does the graph represent a proportional relationship? Explain. What is the constant of proportionality? What is the eq

uation for the graph?
(The graph is in the picture)

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

yes, 10

Step-by-step explanation:

For a graph to represent a proportional relationship, you need 2 things:

1) The graph is a straight line that passes through the origin.

2) The line is not vertical or horizontal.

Here you have a line that is not vertical or horizontal; and passes through the origin (the point (0, 0)  ). Therefore, this line represents a proportional relationship.

To find the constant of proportionality, look for any point except the origin, and divide its y-coordinate by its x-coordinate. The constant of proportionality is also the slope of the line.

For example, pick (1, 10).

constant of proportionality = 10/1 = 10

Answer: yes, 10

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3 years ago
Can I get some help with proofs?<br> Picture is attached
aleksandr82 [10.1K]

Give a reason for each step of the proof. 

Given: <1 and <2 are complimentary 

<1 is congruent to <3, 

<2 is congruent to <4 

Prove: <3 and <4 are complimentary 

Statements: Reasons: 

1. <1 and <2 are complimentary 1.Given 

2. m<1 + m<2=90* 2.<u>DEFINITION OF COMPLEMENTARY ANGLES</u>

3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______ 

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5. m<3 + m<2=90* 5. <u>SUBSTITUTION PROPERTY (m<1 is replaced by m<3.) </u>

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8 0
3 years ago
Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

3 0
3 years ago
Determine the following<br>quadratic equations have real<br>roots<br><br>1) 3x² - √2x-√3​
IceJOKER [234]

Step-by-step explanation:

√3 x² - 2x - √3 = 0

√3 x² - 3x + x - √3 = 0

√3 x(x - √3) + 1(x - √3) = 0

(x - √3 ) (√3 x + 1) = 0

x - √3 = 0 , √3 x +1 = 0

x = √3 , x = -1/√3

3 0
3 years ago
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