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3 years ago

Simplify each product. Write in standard form.

Mathematics

1 answer:

muminat3 years ago

6 0

29. 2w + 13
31. 9r - 4
33. 21q + 10

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Which of the following numbers are greater than or equal to 4/7? Is it 2/5, 0.57, or 2/3. Use explanation why.

Sergeeva-Olga [200]

Answer:

2/3

Step-by-step explanation:

2/5=0.4 and 4/7=0.571428

0.57<0.571428

---------------------------

2/3=0.6667

which is greater than or equal to 4/7

5 0

2 years ago

NEED HELP ON THIS PLEASE! Oregon Trail: Percents.

harina [27]

1845-1846

118->148

148-118 = 30 = change

percent

30/118 ≈ 25.4%

1846-1847

148->139

148-139 = 9 = change

percent

9/148 ≈ 6%

1847-1848

139->151

151-139 = 12 = change

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12/139 ≈ 8.6%

Hope this helped :)

5 0

2 years ago

Is it C or no? Can u help please

Westkost [7]

the answer is Probably C.

7 0

3 years ago

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$

4 0

2 years ago

How do i show my work for 12.62 divide by 0.4

insens350 [35]

3.155

.................

3 0

2 years ago