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valentina_108 [34]
2 years ago
11

Hi pls help me solve this. Need it now. ​

Mathematics
1 answer:
kenny6666 [7]2 years ago
3 0

Answer:

I Had this question moments ago lol

Step-by-step explanation:

The top one is 52 over 110 and the bottom one is 60 over 65!

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The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.​
saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

\sf \:2 π r = r+ 74

\sf \: =   > 2 \times  \frac{22}{7}  \times r =  r \:  + 74

\sf \: =  >  \frac{44r}{7}  -r  = 74

\sf \:  =  > \frac{44r - 7r}{7}  = 74

\sf \: =  >  \frac{37r}{7}  = 74

\sf \: =  > r =  \frac{7 \times 74}{37}

\sf \: =  >  r = 14

  • Hence, the radius of the circle is 14 cm.

________________________________

3 0
2 years ago
Read 2 more answers
Suppose an item is originally
Sonbull [250]

Answer:$21.207 or $21.21

Step-by-step explanation:

You would take $24.95 *85% (that is how much you are going to pay) and the result is your answer

4 0
3 years ago
At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other
Juli2301 [7.4K]
Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
5 0
3 years ago
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What is the slope of a line that passes through (–12,15) and (0,4)?
Romashka [77]
I think that the answer is negative 11 over 12
5 0
3 years ago
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Find BC please in the picture
tatiyna

B. 25 Km. The measure of BC is 25 km.

The easiest way to solve this problem is using the cosine theorem c = √a²+b²-2ab*cos A.

BC = √AC²+AB²-2(AC)(AB)*cos A

BC = √(21km)²+(14km)²-2(21km)(14km)*cos 89°

BC = √441km²+196km²-588km²*(0.017)

BC =√637km²-10.26km²

BC = √636.74km²

BC = 25.03km ≅ 25

7 0
3 years ago
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