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Tanzania [10]
3 years ago
11

What is the area of the triangle given below?

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

70 .formula = 1/2*b*h hope it helps

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What is the LCD of 1/6 and 5/4
slavikrds [6]

Answer:

12

Step-by-step explanation:

6  = 2*3

4 = 2*2

The least common multiple is

2*2*3 = 12

The least common denominator is 12

7 0
3 years ago
Read 2 more answers
Fran is making a punch for her birthday party. She needs 4 1/5 liters of juice for the punch, but she only has 1 4/5 liters. How
labwork [276]

Answer: she needs 2 2/5 liters

Step-by-step explanation:

5 0
3 years ago
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In supply (and demand) problems, y is the number of items the supplier will produce (or the public will buy) if the price of the
SSSSS [86.1K]

Answer:

A) (17 ; 550)

B) $17/item

C) 550

Step-by-step explanation:

First we must calculate the intersection point of the two lines. Since in that point <em>y</em> has the same value in both equations, we can obtain <em>x </em>by equalling the two equations and then using that value for obtaining <em>y</em>:

5x+465=-6x+652\\5x+6x=652-465\\11x=187\\x=\frac{187}{11}\\x=17

So the value of <em>x</em> in the intersection point is 17. We now use this value with either one of the equations to obtain <em>y</em><em>. </em>Let's use the supply equation:

y=5*17+465\\y=550

So the intersection point is (17 ; 550)

Supply and demand are in equilibrium when the amount of items on supply are the same as the ones on demand. That is the point were the two lines intersect, which means the selling price is the <em>x</em> coordinate and the amount of items is the <em>y</em> coordinate, so that is a selling price of <em>$17/item</em> with a number of items of <em>550</em>.

3 0
3 years ago
Need help! Anyone know?
antiseptic1488 [7]
It’s 90 degrees because it’s a right angle
6 0
3 years ago
(5CQ) Use the comparison test to determine whether the series 25/3+125/9+625/27+... is convergent or divergent.
olya-2409 [2.1K]

The terms in the sum are given by the sequence

\left\{\dfrac{5^{n+1}}{3^n}\right\}_{n\ge1}

We have

\dfrac{5^{n+1}}{3^n}>\dfrac{5^n}{3^n}=\left(\dfrac53\right)^n>1

for all n, and the series 1+1+1+\cdots clearly diverges, so \dfrac{25}3+\dfrac{125}9+\cdots must also diverge.

4 0
4 years ago
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