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BartSMP [9]
4 years ago
15

Alicia is writing the program for a video game. For one part of the game she uses the rule (x,y)->(x-3,y+4) to move points on

the screen. A) what output does the rule give when the input is (-6,0)? Show your work B)What output does the rule give when the input is (3,-4)? Show your work C) Is the rule a function? Explain why it is or why it is not
Mathematics
1 answer:
denpristay [2]4 years ago
6 0
A.-6-3 = -9
0+4 = 4 
(-9,4)
B.3-3 = 0
-4+4 = 0 
(0,0)
Yes. it shifts the graph left (-3) and up (+4) with each x or y value. 
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Plz help it’s very confusing
zepelin [54]
So the total is 120. You want 1/6 of those. 
So do (1/6)*120
You get 20.

YAY
6 0
4 years ago
Which of the following represents an equation of of a line with a slope of- 1/4 and an X-intercept of 8?
sdas [7]
<span>Using the form y = mx + b, where m = the slope and b = the y intercept


The x intercept occurs when y = 0, therefore to find b:
-1/4*8 + b = 0
-2 + b = 0
b = 2
therefore our equation is
y = -1/4x + 2,

Sorry it was late

</span>
5 0
4 years ago
Paige works at a department store and has a commission rate of 3 percent. Her sales for the quarter were $4,596. If she earns $5
vagabundo [1.1K]
If she gets 3% of what she sells you multiply the decimal form of the percent by the amount she has made:
50*.03=1.5
So she make $1.50 for every $50 of sales, so you multiply the amount she made by her commission each day by the number of days she worked:
1.5*30=45
 
She earned a total of $45<span />
4 0
3 years ago
Read 2 more answers
May somebody help me? I’m just tryna catch up because this assignment is a deadline
Elina [12.6K]

Answer:

\sqrt{\frac{36}{169} } = \frac{6}{13}

Step-by-step explanation:

First, transform the fraction inside the square root into the following:

\frac{\sqrt{36}}{\sqrt{169}}.

Next, you can take the square root of 36 (\sqrt{36}), which is 6 (6^{2} = 36).

\frac{\sqrt{36}}{139} = \frac{6}{\sqrt{169}}

Then, you can take the square root of 169 (\sqrt{169} ), which is 13 (13^{2} = 169)

\frac{6}{\sqrt{169}} = \frac{6}{13}

3 0
3 years ago
A coin is tossed 5 times. Find the probability that exactly 1 is a tail. Find the probability that at most 2 are tails.
Natalija [7]

Answer:

Step-by-step explanation:

<h2>First question</h2>

The only possibilities where there is exactly 1 tail are:

  1. (t,h,h,h,h)
  2. (h,t,h,h,h)
  3. (h,h,t,h,h)
  4. (h,h,h,t,h)
  5. (h,h,h,h,t)

those are 5 favorable outcomes.

where <em>h represent heads</em> and <em>t represent tails. </em>There are 2^5 32 total number of outcomes after tossing the coin 5 times. Because every time you toss the coin, you have 2 possibilities, and as you do it 5 times, those are 2^5 options. We can conclude from this that

The probability that exactly 1 is a tail is 5/32.

<h2>Second question</h2>

We already know the total number of outcomes; 32.  Now we need to find the number of favorable outcomes. In order to do that, we can divide our search in three cases: <em>1.-there are no tails, 2.-exactly 1 is a tail, 3.- exactly 2 are tails.</em>

The first case is 1 when every coin is a head. The second case we already solved it, and there are 5. The third case is the interesting one, we can count the outcomes as we did in the previous questions, but that's only because there are not too many outcomes.  Instead we are going to use combinations:

We need to have <u>2</u> tails, the other coins are going to be heads. We made <u>5</u> tosses, then the possible combinations are C_{5,2} = \frac{5!}{3!2!} = \frac{120}{6*2} = 10

Finally, we conclude that there are 1 + 5 + 10 favorable outcomes, and this implies that

The probability that at most 2 are tails is \frac{16}{32} = \frac{1}{2}.

4 0
4 years ago
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