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musickatia [10]
2 years ago
6

More of my brothers wwork for yalll have fun and tysm!

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
8 0

Answer:

i cant wait to start are life together, with are son. im so thankful for u becca. ily

Step-by-step explanation:

IceJOKER [234]2 years ago
5 0
Answer: 3/4 x 48
3 x 12
= 36

Got 12 by reducing the numbers with the Greatest Common Factor (GCF) 4
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A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be,
Iteru [2.4K]
The starting value is 20,300, and the value is decreasing by 9.5% each year.

Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.

A decrease by 9.5% corresponds to multiplying by 91.5% each year.

We write . We plug in 11 years for t.

A(t)=23000(0.915)^{t}\\\\A(11)=23000(0.915)^{11}\\\\A(11)=7671.18

$7,671.18
6 0
3 years ago
What is the difference of -2-8
kirza4 [7]

-Answer:

-10

Step-by-step explanation:

the difference is another word for subtract

4 0
3 years ago
Read 2 more answers
A bag contains 4 red marbles, 2 blue marbles, 1 purple marble, and 3 green marbles.
STatiana [176]

Answer:

10 outcomes

Step-by-step explanation:

The number of outcomes is the number of marbles in the bag since we are taking out one marble

4+2+1+3 = 10

There are 10 outcomes

7 0
3 years ago
And, S2
dangina [55]

<u>Correct Question</u>

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

\left|\begin{array}{c|c|c|c}-&-&-&-\\J&K&J&5\\K&K&L&13\\L&J&L&15\\-&-&-&-\\11&7&15\end{array}\right

Answer:

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

\left|\begin{array}{c|c|c|c}-&-&-&-\\1&3&1&5\\3&3&7&13\\7&1&7&15\\-&-&-&-\\11&7&15\end{array}\right

4 0
3 years ago
Are these functions?
OlgaM077 [116]

Answer:

Relation 1 : Not a function

R2 : Function

R3: Function

R4: Not a function

7 0
3 years ago
Read 2 more answers
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