3 years ago

I need help with this problem

Mathematics

1 answer:

marishachu [46]3 years ago

7 0

True

∠2 and ∠5 are both vertical at the vertex of the 2 straight lines

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85 points, Brainliest, ill report random answers>ban

Leya [2.2K]

all the coordinates of the original triangle have been multiplied by 1/2

A (-4,-6) x 1/2 = -2,-3

B (-8,2) * 1/2 = -4,1

C (-2,4) *1/2 = -1,2

so the scale factor is 1/2

Answer is B

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Answer:

the answer is A. y = x + 2/7

Step-by-step explanation:

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Answer:52

Step-by-step explanation:

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Sati [7]

Answer:

$\huge\boxed{\sf \frac{y-5}{y-3} }$

Step-by-step explanation:

<u>Solving it by mid-term break method:</u>

$\displaystyle =\frac{y^2-3y-40}{y^2-11y+24} \\\\= \frac{y^2 -8y+5y-40}{y^2-3y-8y+24} \\\\= \frac{y(y-8)+5(y-8)}{y(y-3)-8(y-3)} \\\\Take \ (y-8) \ and \ (y-3)\ common\\\\= \frac{(y-8)(y-5)}{(y-8)(y-3)} \\\\= \frac{y-5}{y-3} \\\\\rule[225]{225}{2}$

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