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3 years ago

I need help with this problem

Mathematics

1 answer:

marishachu [46]3 years ago

7 0

True

∠2 and ∠5 are both vertical at the vertex of the 2 straight lines

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Prove that there is a positive number x such that x^3=5

astra-53 [7]

$x^3=5\\ x=\sqrt[3]5$

and $\sqrt[3]5$ is positive

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3 years ago

Find the distance between A and B.

Andreas93 [3]

Answer:

$\sqrt{34}$ units

Step-by-step explanation:

A = (-4,-1)

B = (1,2)

distance between 2 points:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1} )^{2}}\\\\d=\sqrt{(1-(-4))^{2}+(2-(-1))^{2}}\\ \\d=\sqrt{(5)^{2}+(3)^{2}}\\\\d=\sqrt{34}$

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3 years ago

Which is equivalent to cube root 8^x?

VARVARA [1.3K]

Answer:

Step-by-step explanation:

³√8 = 2

hope it's helpful

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3 years ago

If the nth term of a sequence is 3n+2 them T³= T⁵=T¹⁵=

Katena32 [7]

Answer:

T^75

Step-by-step explanation:

3 times 5 = 15

5 times 15 = 75

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3 years ago

Suppose x is a normally distributed random variable with a mean of 12 and a standard deviation of 3. The probability that x equa

Contact [7]

Answer:

The probability that x equals 19.62 is 0

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In the normal probability distribution, the probability of an exact value, that is, P(X = x) is 0. Thus, the probability that x equals 19.62 is 0

8 0

3 years ago