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lilavasa [31]
3 years ago
7

Need help with math probelm

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0

28+24=4(7)+4(6)=4(7+6)[=4(13)=52]

The answer: 4(7+6)

ok done. Thank to me :>

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There are 33 boxes of erasers in the supply closet. Each box contains 34 erasers. How many erasers are there in all?​
Sedbober [7]

Answer:

The answer is 1,122

Step-by-step explanation:

33 x 34

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3 years ago
Find the 2 numbers whose sum is 51 and whose difference is 13
son4ous [18]
2 #'s whose sum is 51: x + y = 51
2 #'s whose difference is 13: x - y = 13

add the 2 equations: 2x = 64 ⇒ x = 32
using either equation find y: 32 + y = 51 ⇒ y = 19
Answer the 2 #'s are 32 and 19
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Chris knows that the formula for finding the volume of a cone is:
kipiarov [429]

It is given in the question that the formula of volume of cone is

V = \frac{1}{3} \pi r^2 h

Where V is the volume, r is the radius and h is the height.

And we have to find an expression for h.

First we multiply both sides by 3, and on doing that we will get

3 V= \pi r^2h

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Therefore the correct option is B.

3 0
3 years ago
Read 2 more answers
Hi! I need the answer to: 92x5(75+85)x200-5=___? Thanks
Leni [432]
<span>92x5(75+85)x200-5= 14,719,995</span>
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4 years ago
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Use part 1 of the fundamental theorem of calculus to find the derivative of the function. g(x) = x t3 t5 dt 0
salantis [7]

Using the fundamental theorem of calculas the derivative of function g(x)=xt^{3}+t^{5} at x=0 is t^{3}.

Given a function g(x)=xt^{3}+t^{5}.

We are required to find the derivative of the function g(x) at x=0.

Function is relationship between two or more variables expressed in equal to form. The values entered in a function are part of domain and the values which we get from the function after entering of values are part of codomain of function. Differentiation is the sensitivity to change of the function value with respect to a change in its variables.

g(x)=xt^{3}+t^{5}

Differentiating with respect to x.

d g(x)/dx=t^{3}+0  [Differentiation of x is 1 and differentiation of constant is 0]

=t^{3}

Hence using the fundamental theorem of calculas the derivative of function g(x)= xt^{3}+t^{5} at x=0 is t^{3}.

The function given in the question is incomplete. The right function will be g(x)=xt^{3}+t^{5}.

Learn more about differentiation at brainly.com/question/954654

#SPJ4

.

5 0
1 year ago
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