A horse has a speed of 10 miles per hour

Which equation can be used to solve the problem? 10 is 50 percent of what number? StartFraction 10 divided by 1 Over 50 divided

IceJOKER [234]

Answer:

D

Step-by-step explanation:

i took the test trust me

3 0

3 years ago

Read 2 more answers

Which number has both 2 and 5 as prime factors?

musickatia [10]

Answer:

Any multiple of 10

Step-by-step explanation:

A factor is defined as "a number or quantity that when multiplied with another produces a given number or expression." For example, the factors of 20 are 1, 2, 4, 5, 10, and 20.

When we multiply 2 and 5 together, we get 10. Multiplying this by anything else besides 0 will still yield something that has 2 and 5 as factors, for example 2 times 5 times 3 is 30. As this is just the same thing as multiplying 10 by 3, the answer is any multiple of 10.

4 0

3 years ago

A graph titled Passing Statistics has pass attempts on the x-axis, and yards on the y-axis. A line goes through points (24, 127)

bogdanovich [222]

Answer:

1/3x

Step-by-step explanation:

Subtract x by x and y by y to find the distance/difference

36 163

24, 127

= 12/36 = rise/run

Now reduce to find the slope, reduce until you can't anymore.

12/36

6/18

3/9

1/3 (that's your slope)

4 0

3 years ago

-8.5÷3.4 how to solve this step by step

sertanlavr [38]

You have to move both decimals over and then divide. So the answer is 25.

3 0

3 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$