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algol13
2 years ago
10

Please help me thank you

Mathematics
1 answer:
saveliy_v [14]2 years ago
6 0

Answer:

multiplication. answer below

Step-by-step explanation:

  1. 40
  2. -30
  3. 25
  4. 20
  5. 5
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Does the average person live for at least 1,000,000 minutes?
irakobra [83]
Convert to hours, then days, then years
60 minutes per hour
1000000/60=50000/3=16666.7 hours

24 hours per day
16666.7/24=694.4 days
365 days per year
694.4/365=1.9

the average person lives at least 1.9 years
maybe, I guess
6 0
3 years ago
Read 2 more answers
A: What is the smallest increment on the voltmeter
oee [108]

Answer:

RESOLUTION

Step-by-step explanation:

Resolution is the smallest increment a tool can detect and display. For a nonelectrical example, consider two rulers.

4 0
3 years ago
Karli produces organic cheese from milk supplied by an organic dairy. Karli pays an average of $8.00 for 10 gallons of the organ
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d. $43.00

Step-by-step explanation:

Karli's total cost is ...

total cost = material cost + labor cost

= ($8.00/10 gal)·(5 gal) + ($13.00/h)·(3 h)

= $4.00 + $39.00

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4 0
3 years ago
The diameter of a circle has endpoints whosever coordinates are R(-2,2) and S(4,2). find the center of the circle
ZanzabumX [31]
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8 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
4 years ago
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