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3 years ago

On a certain day, the temperature

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

6 0

It took 11 hours to change!

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the lengths of the four sides as a quadrilateral (in feet) are consecutive integers if the perimeter is 86 ft find the value of

tia_tia [17]

Let x be the shortest side

Let x+1 be the second side

Let x+2 be the third side

Let x+3 be the fourth and longest side

$perimeter = s_{1} + s_{2} + s_{3} + s_{4} \\ 86 = x + (x + 1) + (x + 2) + (x + 3) \\ 86 = x + x + 1 + x + 2 + x + 3 \\ 86 = 4x + 6 \\ 4x = 80 \\ x = 20$

Shortest side is 20 cm

Longest side is x+3 so 20+3=23

<h2>Answer: 23</h2>

5 0

1 year ago

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
 $2x^{2} + 14x - 3x - 21 = 0$
 $2x^{2} + 11x - 21 = 0$

 $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

 $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

 $x = \frac{-11 +/- \sqrt{289}}{4}$

 $x = \frac{-11 +/- 17}{4}$

 $x = -2.75 +/- 4.25$
 $x = -2.75 + 4.25$ $x = -2.75 - 4.25$
 $x = 1.5$ $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
 $8x(2x) - 8x(5) = 0$
 $16x^{2} - 40x = 0$
 $16x^{2} - 4x + 0 = 0$

 $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

 $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

 $x = \frac{40 +/- \sqrt{1600}}{32}$

 $x = \frac{40 +/- 40}{32}$

 $x = 1.25 +/- 1.25$
 $x = 1.25 + 1.25$ $x = 1.25 - 1.25$
 $x = 2.5$ $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

 $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

 $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

 $x = \frac{-3 +/- \sqrt{49}}{2}$

 $x = \frac{-3 +/- {7}}{2}$

 $x = -1.5 +/- 3.5$
 $x = -1.5 + 3.5$ $x = -1.5 - 3.5$
 $x = 2$ $x = -5$
----------------------------------------------------------------------------------------------------------
4. $x^{2} = 13x - 36$
 $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
 $x^{2} - 13x + 36 = 0$

 $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


 $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

 $x = \frac{13 +/- \sqrt{25}}{2}$

 $x = \frac{13 +/- 5}{2}$

 $x = 6.5 +/- 2.5$
 $x = 6.5 + 2.5$ $x = 6.5 - 2.5$
 $x = 9$ $x = 4$
----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

 $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

 $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

 $x = \frac{7 +/- \sqrt{41}}{6}$

 $x = \frac{7 +/- 6.403124237432849}{6}$

 $x = 1.167+/- 1.06718737290547$
 $x = 1.67 + 1.06718737290547$ $x = 1.167 - 1.06718737290547$
 $x = 2.73718737290547$ $x = 0.60281262709453$
----------------------------------------------------------------------------------------------------------
6. $10x^{2} - 10x + 9 = 5x^{2} + 4x + 1$
 $10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1$
 $5x^{2} + 8 = 14x$
 $5x^{2} - 14x + 8 = 14x - 14x$
 $5x^{2} - 14x + 8 = 0$

 $x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}$

 $x = \frac{14 +/- \sqrt{196 - 160}}{10}$

 $x = \frac{14 +/- \sqrt{36}}{10}$ .

 $x = \frac{14 +/- 6}{10}$

 $x = 1.4 +/- 0.6$
 $x = 1.4 + 0.6$ $x = 1.4 - 0.6$
 $x = 2$ $x = 0.8$

5 0

4 years ago

Use substitution to solve the linear system of equations

xenn [34]

we are given

system of equations

$y=4x$

$3x+5y=-46$

we can plug first equation into second equation

we get

$3x+5(4x)=-46$

Simplify left side

$3x+20x=-46$

$23x=-46$

Divide both sides by 23

and we get

$x=-2$

now, we can find y-value

$y=4*-2$

$y=-8$

so, our solution is

$(x,y)=(-2,-8)$ .............Answer

4 0

3 years ago

Please help! 30 points and brainliest.

Leya [2.2K]

You would have to flip the first shape to face the same direction as the second one. the corresponding line to ab is sr, bc to sp, ad to rq, and cd to pq :)

5 0

3 years ago

Read 2 more answers

The satang coin from Thailand has a radius of about 7 mm

Veseljchak [2.6K]

Given:

The satang coin from Thailand has a radius of about 7 mm.

We need to determine the diameter and circumference of the coin.

Diameter of the coin:

The diameter of the coin can be determined by multiply the radius by 2.

Thus, we have;

$d=2r$