No If the coin was fair the 2 values should be closer together. The probability of a head ( and a tail) should be close to 1/2 for a fair coin.
Let Mary Sue have m necklaces and Betty have b necklaces.
And they have 603 necklaces altogether, that is
m + b =603
And Mary Sue has 115 more necklaces than Betty, that is
m=b +115
Substituting this value in first equation we will get
b+115+b=603
Subtracting 115
2b= 488
b= 244
So Betty have 244 necklaces .
Answer:
1) 7
2) 11
3)9
Step-by-step explanation:
i dont feel like explaining
Answer:
The slope is 0
Step-by-step explanation:
Points on the graph:
(5, -4) and (7, -4)
Slope:
m=(y2 - y1)/(x2 - x1)
m=(-4 + 4)/(7 - 5)
m= 0/2
m=0
Answer:
2q+6
Step-by-step explanation:
So basically, you would do this.
-2q-6+6q+12-2q
Next
-4q+6q = 2q
12-6=6
2q+6
