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Molodets [167]
3 years ago
13

Starting salaries of 90 college graduates who have taken a statistics course have a mean of $43,993 and a standard deviation of

$9,144. Using 99% confidence level, find the following:
A. The margin of error E:________
B. The confidence interval for the mean: μ__________< μ<_____________

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer: attached below

Step-by-step explanation:

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25.2 min

Step-by-step explanation:

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Read 2 more answers
PLEASE!!!!! HELP ME!!!!!!
kati45 [8]

Answer:

15 = a_1 r^4 (1)

1 = a_1 r^5 (2)

If we divide equations (2) and (1) we got:

\frac{r^5}{r^4}= \frac{1}{15}

And then r= \frac{1}{15}

And then we can find the value a_1 and we got from equation (1)

a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375

And then the general term for the sequence would be given by:

a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

Step-by-step explanation:

the general formula for a geometric sequence is given by:

a_n = a_1 r^{n-1}

For this case we know that a_5 = 15, a_6 = 1

Then we have the following conditions:

15 = a_1 r^4 (1)

1 = a_1 r^5 (2)

If we divide equations (2) and (1) we got:

\frac{r^5}{r^4}= \frac{1}{15}

And then r= \frac{1}{15}

And then we can find the value a_1 and we got from equation (1)

a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375

And then the general term for the sequence would be given by:

a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

4 0
3 years ago
Howcto write 9,000,009 in word form
Licemer1 [7]
Nine million and nine
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%5Csqrt%7Bx%7D%20-1%5Cleq%2012" id="TexFormula1" title="3\sqrt{x} -1\leq 12" alt="3\sqrt{x} -
densk [106]

Answer:

0≤x≤169/9

Step-by-step explanation:

6 0
3 years ago
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