2 answers:

<AEC =X°
<h3>first draw line passing with E</h3><h3 /><h3>and then ,now</h3><h3 />
<EAB = 116°
the by (consecutive)
180 = <EAB + <1
<1 = (180 - 116 )
<1=. 64°
<h3>now second step,</h3>
<ECD = 124°
then ,180 = <ECD + <2
<2= (180 - 124)
<2= 56°
= Now add <1 + <2
= (64+ 56)°
➡x° = 120°
Answer:
Solution given:
Construction:
EF parallel to AB and CD is drawn.
let suppose <AEF=a
and
<CEF=b
now
<EAB+<EAB=180°[being co interior angle]
116°+a=180°
a=180°-116°=64°
again
<DCE +<CEF=[being co interior angle]
124°+b=180°
b=180°-124°
b=56°
Now
we know
x=a+b=64°+56°=120°
<u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>x</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>2</u><u>0</u><u>°</u>
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