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tatiyna
3 years ago
10

Hi, I need help with all of these questions! (screenshots included) Thank you! I really appreciate it.

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

I'm unsure about the first one, but the second one is irrational, the third one is option C, the fourth is option b, and the last one is D i believe

Step-by-step explanation:

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Combing like terms in an quadiatic expression <br><br>2x2-10x-8+7x
Readme [11.4K]
OH DONT COPY THIS M8
THIS IS WRONG

4 0
3 years ago
6.<br>Share £120 in the ratio 5: 2:5. (Total 12 parts)​
OverLord2011 [107]

Answer:

50:20:50

This is because you add 5+2+5=12

120/12=10

5x10=50 2x10=20 5x10=50

4 0
3 years ago
Read 2 more answers
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
The model represents x2 – 9x + 14. An algebra tile configuration showing only the Product spot. 24 tiles are in the Product spot
klio [65]

I didn't get all the part with the tiles, but here's the general answer:

given a polynomial

p(x)=ax^2+bx+c

we have that x-k is a factor of p(x) if and only if k is a root of p(x), i.e. if

p(k)=ak^2+bk+c=0

So, given the polynomial

p(x)=x^2-9x+14

We can check if x-9 is a factor by evaluating p(9):

p(9)=81-81+14=14\neq 0

So, x-9 is not a factor.

Similarly, we can evaluate p(2),\ p(-5),\ p(-7) to check if x-2,\ x+5,\ x+7 are factors:

p(2)=4-18+14=0,\quad p(-5)=25+45+14=84\neq 0,\quad p(-7)=49+63+14=126 \neq 0

So, only x-2 is a factor of x^2-9x+14

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!
irakobra [83]

Answer:

D

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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