That's OK, but you have not said which variable you want to solve it for.

To solve for 'x':
 c + ax = dx

Subtract c from each side: ax = dx - c

Subtract dx from each side: ax - dx = -c

Factor the left side: x (a - d) = -c

Divide each side by (a - d) : x = -c / (a - d) or x = c / (d - a) .

To solve for 'c': 
 c + ax = dx

Subtract ax from each side and factor: c = x (d - a) 

To solve for 'd': 
 c + ax = dx

Divide each side by 'x': d = c/x + a .

To solve for 'a':
 c + ax = dx

Subtract 'c' from each side: ax = dx - c

Divide each side by 'x': a = d - c/x .
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6 0

3 years ago

A battery with 20% of its full capacity is connected to a charger. Every minute that passes, an additional 5% of its capacity is

Masja [62]

Answer:

Step-by-step explanation:

y = 5x + 20

Start at (0, 20).

Then plot a point at (1, 25).

The line should be going through points (2, 30), (3, 35), (4, 40), (5, 45), etc.

For every time the x number goes up, the y number goes up 5 times for the 5%.

3 0

3 years ago

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