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Thepotemich [5.8K]

2 years ago

10

Bruce walks 3/4 mile in 1/5 hour. What is his speed in miles per hour? (label your answer mph) * worth 25 points and brainlyiest

pls no links or deleting this Ty

1 answer:

LenKa [72]2 years ago

3 0

The answer to this question is 3.75

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An employee makes a gross salary of 48,000 per year 15% of that money goes toward taxes of the employee invest 20% of his gross

kolezko [41]

First calculate his gross salary after his 401k contributions:
$x = 48000 - (48000 \times 0.20) \\ x = 38400$

Then find the amount of taxes withheld:
$t = 38400(0.15) \\ t = 5760$

5,760 dollars went towards taxes.

6 0

3 years ago

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Give the exact form and decimal form of the equation

Svet_ta [14]

Answer:

Exact form: $\sin{(6x)} = \frac{8}{9}$

Decimal form: $\sin{(6x)} = 0.8889$

The solution for x is: The solution for x is of 10.455º

Step-by-step explanation:

We are given the following equation:

$8 = 9\sin{(6x)}$

Placing into the desired format, the exact format is:

$\sin{(6x)} = \frac{8}{9}$

In the decimal part, we divide 8 by 9. So

$\sin{(6x)} = 0.8889$

Solving for x:

We apply the inverse sine. So

$\sin^{-1}{\sin{(6x)}} = \sin^{-1}{0.8889}$

$6x = 62.73$

$x = \frac{62.73}{6}$

$x = 10.455$

The solution for x is of 10.455º

5 0

2 years ago

Which answer explains the correct way to move the decimal to find the product of 23.8 x 100?

Mars2501 [29]

Move the decimal 2 places to the right resulting in the answer 2,380

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B91%20-%2040%5Csqrt%7B3%7D%20%7D" id="TexFormula1" title="\sqrt{91 - 40\sqrt{3} }" al

lianna [129]

Answer:

$5\sqrt{3} - 4$

Step-by-step explanation:

$\sqrt{(4-5\sqrt{3} )^{2} }$

$5\sqrt{3} - 4$

3 0

3 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

or

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

or

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

3 years ago

Read 2 more answers