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Margaret [11]
2 years ago
5

How do you know if a net will fold into a pyramid?

Mathematics
1 answer:
Natalka [10]2 years ago
4 0

Step-by-step explanation:

A pyramid is made when 4 triangle meet on square then mate on each together .

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The difference of a number and 8 is no more then 13
skad [1K]

x - 8 = </= 13

x could be from 9 to 21

6 0
3 years ago
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
This change will cause equilibrium Price and Quantity to
Annette [7]
C ) price Decrease and quantity decrease
6 0
3 years ago
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W
Travka [436]

Complete question:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

A"B" = \frac{AB}{2}

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

A"B" = AB * \frac{1}{2}

A"B" = \frac{AB}{2}

The equation that explains the relationship between segment AB and segment A"B" is

A"B" = \frac{AB}{2}

Option A is correct

5 0
2 years ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
Read 2 more answers
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