a counterclockwise rotation about the origin of 90°
The coordinates of P(3, 3), Q(5, 3), R(5, 7)
The coordinates of P'(- 3, 3 ), Q'(- 3, 5), R'(- 7, 5)
Note that the y-coordinate of the image is the negative of the original, while the x-coordinate of the original becomes the y-coordinate of the image
The rotation which does this is a counterclockwise rotation about the origin of 90°
a point (x, y ) → (- y, x )
Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get
The required equation of the quadratic function is where, a is a constant.
Putting a=1, we get
![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is .
Answer:
Step-by-step explanation:
So the sign means that y has to be less than or equal to x plus 9
if you wanted an answer an example could be
y = 1
x = 10
this works because if implemented into the equation
1 ≤ 10 + 9 which is true
Answer:
4/6 or 2/3
Step-by-step explanation:
Using Common denominators:
3/6 = 1/2
1/6 + 3/6 = 4/6
This can reduce to 2/3
