How can you simplify this expression?

Calculus graph please help

tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of y = f'(x) and we want to determine the characteristics of f(x).

Part A)

f is increasing whenever f' is positive and decreasing whenever f' is negative.

Hence, f is increasing for the interval:

$(-\infty, -2) \cup (-1, 1)\cup (3, \infty)$

And f is decreasing for the interval:

$\displaystyle (-2, -1) \cup (1, 3)$

Part B)

f has a relative maximum at x = c if f' turns from positive to negative at c and a relative minimum if f' turns from negative to positive to negative at c.

f' turns from positive to negative at x = -2 and x = 1.

And f' turns from negative to positive at x = -1 and x = 3.

Hence, f has relative maximums at x = -2 and x = 1, and relative minimums at x = -1 and x = 3.

Part C)

f is concave up whenever f'' is positive and concave down whenever f'' is negative.

In other words, f is concave up whenever f' is increasing and concave down whenever f' is decreasing.

Hence, f is concave up for the interval (rounded to the nearest tenths):

$\displaystyle (-1.5 , 0) \cup (2.2, \infty)$

And concave down for the interval:

$\displaystyle (-\infty, -1.5) \cup (0, 2.2)$

Part D)

Points of inflections are where the concavity changes: that is, f'' changes from either positive to negative or negative to positive.

In other words, f has an inflection point wherever f' has an extremum point.

f' has extrema at (approximately) x = -1.5, 0, and 2.2.

Hence, f has inflection points at x = -1.5, 0, and 2.2.

7 0

3 years ago

Pls answer this! I need to pass!

KengaRu [80]

Answer:

b

Step-by-step explanation:

6 0

3 years ago

Which expression is equivalent to...

olga_2 [115]

Answer:

$8m^5$

Step-by-step explanation:

Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)

This gives us the fraction: $\frac{24m^7}{3m^2}$

We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction: $\frac{24 * m * m * m * m * m * m * m}{3 * m * m}$

Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:

$\frac{24 * m * m * m * m * m}{3}$ which can be simplified in exponent form as: $\frac{24m^5}{3}$ , now all we have to do is divide the 24 by the 3, to get 8