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gogolik [260]
3 years ago
8

Pls answer this! I need to pass!

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Wanda rode her bike 5km the first day and she rode her bike 10,000m the second day. How many meters, in total, did Wanda ride in
vladimir2022 [97]

Answer:

there are one thousand (1,000) meters in a kilometer. So, 5,000 plus 10,000 is 15,000 meters.

Step-by-step explanation:

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3 years ago
1. Leland started a savings account with
Alborosie

Answer:18 weeks

Step-by-step explanation:

3 0
3 years ago
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Julian is trying to decide on a future career. He has narrowed down his choices to orthodontist, sound engineering technician, p
Alenkasestr [34]

Percentage is the way to represent the part of a whole in a fraction of 100.The greatest percent of the increase in the number of jobs from 2006 to 2016 is orthodontist which is 10.94 percent.

<h3>Given-</h3>

In the given table we have to find out the percent of the increase in the number of each job to find out the greatest one.

<h3>Percentage</h3>

Percentage is the way to represent the part of a whole in a fraction of 100.

1-Orthodontist-

In 2006 the total number of orthodontists was 9206.

In 2016 the total number of orthodontists was 10214

Percent of increase in this job is,

p_{1} =\dfrac{10214-9206}{9206}\times100

p_{1} =10.94%

Hence, percent of the increase in this job is 10.94 present.

2-Sound engineer technician-

In 2006 the total number of Sound engineer technicians was 16125

In 2016 the total number of Sound engineer technicians was 17864

Percent of increase in this job is,

p_{2} =\dfrac{17864-16125}{16125}\times100

p_{2} =10.78%

Hence, percent of the increase in this job is 10.78 percent.

3-Police officer-

In 2006 the total number of Police officers was 648982

In 2016 the total number of Police officers was 719041

Percent of increase in this job is,

p_{3} =\dfrac{719041-648982}{648982}\times100

p_{3} =10.79%

Hence, percent of the increase in this job is 10.79 percent.

4- Editor-

In 2006 the total number of Editors was 122273

In 2016 the total number of Editors was 124135

Percent of increase in this job is,

p_{2} =\dfrac{124135-122273}{122273}\times100

p_{4} =1.52%

Hence, percent of the increase in this job is 1.52 percent.

Hence, the greatest percent of the increase in the number of jobs from 2006 to 2016 is orthodontist which is 10.94 percent.

Learn more about the percentage here;

brainly.com/question/21230679

4 0
3 years ago
The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in amb
Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

4 0
3 years ago
I need to know how to simplify this equation
ArbitrLikvidat [17]

\frac{ {3}^{x + 4} -  {3}^{2x + 2}  }{ {3}^{x - 2} \times  {3}^{x + 4}  }  =   \frac{x + 4 - 2x - 2}{(x - 2) \times (x + 4)}  =  \frac{ - x + 2}{ {x}^{2} + 4x - 2x - 8 }  =  \frac{ - x + 2}{ {x}^{2}  + 2x - 8}
i could be wrong, was kinda in a rush
4 0
3 years ago
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