If 5 consecutive integers is 205,
then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1
⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39
∴ third term = 39 + 2
= 41
Answer:
B. The typical value is greater in set A. The spread is greater in set B.
Answer:
0.03259..
Step-by-step explanation:
It’s C mate! Hope this helps! :))
