If she have 12 pencils and she gave 3/4 away then she will have 3 pencils left.
Maybe 88 not sure that is the givin
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000
Answer:
25π
Step-by-step explanation:
1) for whole circuit: A=π*r², where r - radius of the given circle;
2) for a quater of the circuit: A=πr²/4;
3) finally, A=π*100/4=25π.
Answer:
the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%
Step-by-step explanation:
Martha = widow's peak + attached earlobes.
Martha's dad = straight hairline + unattached earlobes.
Martha husband =straight hairline+ widow's peak + attached earlobes
what is the probability that Martha child will have a widow's peak + attached earlobes?
since,
Martha + Martha husband =straight hairline+ widow's peak + attached earlobes
the probability of the child having widow peak is 2/3 = 0.6667
the probability of the child having attached earlobes is 2/3 = 0.66667
the probability of having both = 0.6667*0.66667 = 0.4445