Question

Need help with this question brainliest for correct answer

Answer 1

Answer:

$\huge\boxed{y=\dfrac{4}{3}x-1}$

Step-by-step explanation:

Let

$k:y=m_1x+b_1\\l:y=m_2x+b_2$

then

$k\perp l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2$

==========================================

We have:

$y=-\dfrac{3}{4}x-3\to m_1=-\dfrac{3}{4}$

Let

$y=m_2x+b_2$

Therefore

$m_2=-\dfrac{1}{-\frac{3}{4}}=\dfrac{4}{3}\Rightarrow y=\dfrac{4}{3}x+b_2$

Substitute

$(0,\ -1)\to x=0;\ y=-1$

$-1=\dfrac{4}{3}\cdot0+b_2\\\\b_2=-1$