I need help with a question in algebra 2. May you please help me? If that’s fine with you?
        
             
        
        
        
Answer:
La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}
Step-by-step explanation:
 
        
             
        
        
        
Step-by-step explanation:
done
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Answer:
1
Step-by-step explanation:
Multiply 1/3 x 1 so you can simplify 1/3 to 1/3 but other wise 2/6 is 1/3 3/9 is 1/3 and etc
 
        
             
        
        
        
Answer:

Step-by-step explanation:
Step 1:
Let us find the missing side. We know this is a <u>right triangle</u>, so we can use the pythagorean thereom to find the last side. Let us set 12 as variable <em>a</em>, 20 as variable <em>c</em>, and the unknown side as variable <em>b</em>.

We do know that a <u>length can never be negative</u>, so the side <em>b</em> would be 16.
Step 2:
According to SOHCAHTOA, cosine is utilizes the adjacent and hypotenuse of the given angle theta. Let us write the equation:

<em>I hope this helps! Let me know if you have any questions :)</em>