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1 year ago

4.11.4 Snake Eyes code HS I cant see to get this right, ant help would be appreciated.

Computers and Technology

1 answer:

Pani-rosa [81]1 year ago

8 0

Answer:

This is python, I don't know what type of programming language you are learning.

import random

# Enter your code here

dice1 = random.randint(1,6)

dice2 = random.randint(1,6)

total = 0

while True:

if dice1 == 1 and dice2 == 1:

total += 1

print("Rolled: " + str(dice1) + " " + str(dice2))

break

else:

total += 1

print("Rolled: " + str(dice1) + " " + str(dice2))

dice1 = random.randint(1,6)

dice2 = random.randint(1,6)

print("It took you "+ str(total) + " rolls to get snake eyes.")

Explanation:

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2 years ago

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Step2247 [10]

Answer:

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2 years ago

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1 year ago

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Nat2105 [25]

Answer:

Kindly check attached picture

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2 years ago

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Natasha2012 [34]

Answer:

The longest codeword that could possibly be for "n" symbol is n-1 bits.

Explanation:

From the given information:

Suppose we are to consider a set of frequencies $\mathtt{f_1,f_2,f_3 ...,f_n}$ , for which f is a symbol for the length n. Therefore, the longest codeword that could possibly be for "n" symbol is n-1 bits.

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2 years ago