f(x).g(x) = (x^2+6x)(2x^3) = 2x^5+12x^4
f(0).g(2) =(0^2+6*0)(2*2^3) =0*16=0
f(1).g(1)=(1^2+6*1)(2*1^3)=(1+6)(2*1)=7*2=14
g(x).g(x)=(2x^3)(2x^3)=2*2*x^3*x^3=4x^6
Answer:
18
Step-by-step explanation:
Answer:
1. I am not sure about the first one. I tried everything and nothing I got from any of my work is looking right.
2. AB = 5
3. 8
Answer:
Every week, the mass of the sample is multiplied by a factor of 0.81
Step-by-step explanation:
Let's rewrite the base and find the expression whose exponent is just ttt.
(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5
Therefore, we can rewrite the modeling function as follows.
M(t)=(0.97)5⋅(0.977)t
According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.
