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3 years ago

I need help ! Find the perimeter of the figure below

Mathematics

1 answer:

hichkok12 [17]3 years ago

4 0

Answer:

The answer to your question is: 82 in

Step-by-step explanation:

Perimeter = the sum of all the sides

Perimeter = 15 in + 8 in + 13 in + 25 in + 13 in + 8 in

= 82 in

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babunello [35]

Answer: 1

Step-by-step explanation:

$\dfrac{ {4}^{2} }{16}=\dfrac{16}{16} =1$

7 0

3 years ago

Read 2 more answers

What is 2p6−19=−9 I need help pls I don't understand this at all

Aleonysh [2.5K]

Answer:

5/6. Is this what u are looking for?

Step-by-step explanation:

Step 1 Simplify:2x(6)-19=-9 to 12x+-19=-9

Step 2 Add 19 to both sides: 12x-19+19=-9+19. You should get 12x=20

Step 3 Divide 12 on both sides: 12x/12=10/12

x=10/12. Simplified= x=5/6

7 0

3 years ago

Jonathan deposited $20 in a savings account earning 5% interest, compounded annually.

Semenov [28]

Answer:

12$

Step-by-step explanation:

3 0

3 years ago

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. Your hourly wage is $8 per ho

elixir [45]

I belive your answer is 320
Happy to assist you!

7 0

4 years ago

A 10-foot ladder is to be placed Against the side of the building. The base of the latter must be placed in an angle of 72° With

12345 [234]

Answer:

Distance of foot of ladder from building: 37.2 inches

Distance of top of ladder from building's base: 114 inches

Step-by-step explanation:

Please refer to the figure attached in the answer area.

A right angled triangle $\triangle ABC$ is formed by the ladder with the building where hypotenuse is the length of ladder.

Hypotenuse, AC = 10 foot

Also, we are given that angle made by the base of ladder with the ground is $72^\circ$ .

We have to find AB and BC.

$\angle BAC = 72^\circ$

Using trigonometric functions:

$cos \theta= \dfrac{Base}{Hypotenuse}\\cos 72^\circ= \dfrac{AB}{AC}\\\Rightarrow 0.309 = \dfrac{AB}{AC}\\\Rightarrow AB = 10 \times 0.309\\$\approx$ 3.1 foot\\$\approx$ 37.2 inches$

$sin \theta = \dfrac{Perpendicular}{Hypotenuse}\\\Rightarrow sin72^\circ = \dfrac{BC}{AC}\\\Rightarrow 0.95 = \dfrac{BC}{AC}\\\Rightarrow AB = 10 \times 0.95\\$\approx$ 9.5 foot\\$\approx$ 114 inches$

Distance of foot of ladder from building: 37.2 inches

Distance of top of ladder from building's base: 114 inches

8 0

3 years ago