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Ber [7]
3 years ago
9

A

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

3:5

Step-by-step explanation:

Let's create a ratio

Mushroom : Cheese

15 : 25

⬆The ratio above can be simplified

Divide both sides by 5

3 : 5

The answer is 3:5

Hope this helps :)

Have a nice day!

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The sides of a rectangle are in the ratio 4:7. If its longer side is 31.5 in., find the shorter side, the perimeter, and the are
Lemur [1.5K]

Answer:

Width = 18 inches

Perimeter = 99 inches

Area = 567 square inches

Step-by-step explanation:

The sides of a rectangle are in the ratio 4:7. Then

Width =4x in

Length =7x in.

If  its longer side is 31.5 in, then

Length = 31.5 in

and

7x=31.5\\ \\x=\dfrac{31.5}{7}=4.5\ in

So,

Width =4\cdot 4.5=18\ in

The perimeter is

P=2(\text{Width}+\text{Length})\\ \\=2(18+31.5)\\ \\=2\cdot 49.5\\ \\=99\ in

The area is

A=\text{Width}\cdot \text{Length}\\ \\=18\cdot 31.5\\ \\=567\ in^2

5 0
3 years ago
Find the x-intercept and
stepan [7]
X intercept (5,0)
Y intercept (0, 2)

Hope that helps

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Which table represents a linear function
I am Lyosha [343]

It is the first one because the X side is going up at a steady rate and the Y is also going up at a steady rate

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Lakiesha is fly a kite the string is 29 feet long and the height of the kite is at 20 ft her dog is currently underneath the kit
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3 0
3 years ago
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A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses wi
murzikaleks [220]

Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   \frac{n_1p_1 +n_2p_2}{n_1+n_2}

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

so  q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

4 0
3 years ago
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