Question

ROCKETS The height in feet of a rocket t seconds after launch is modeled

Answer 1

The average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s

Given the equation as a model, h(t) =–16t² + 72t.

Average speed from 3 to 4 seconds = $\frac{h(4) - h(3)}{4 - 3}$

Find h(4):

h(t) =–16t² + 72t

• Substitute 4 for t in the equation h(t) =–16t² + 72t

h(4) = -16(4)² + 72(4)

h(4) = -256 + 288

h(4) = 32

Find h(3):

h(t) = -16t² + 72t

• Substitute 3 for t in the equation h(t) =–16t² + 72t

h(3) = -16(3)² + 72(3)

h(3) = -144 + 216

h(3) = 72

Plug in the value into  $\frac{h(4) - h(3)}{4 - 3}$:

average speed from 3 to 4 secs = $\frac{32 - 72}{4 - 3} = -40$

Therefore, the average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s

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