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postnew [5]
3 years ago
8

. Megan is standing 300ft from the Eiffel Tower. The Eiffel Tower is 900 ft tall.

Mathematics
2 answers:
Gala2k [10]3 years ago
7 0

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

Angle required = Height of Eiffel Tower/Megan standing place × arctan

=> (900/300) × arctan

=> 3 × arctan

=> 3arctan

=> 71.6⁰

Hence,

Angle = 71.6⁰

\\

MAVERICK [17]3 years ago
5 0

9514 1404 393

Answer:

  about 71.6°

Step-by-step explanation:

The relevant trig function is ...

  Tan = Opposite/Adjacent

Here, the "opposite" side of the right triangle is the height of the tower. The "adjacent" side is the distance to the tower. Then if the angle is x, we have ...

  tan(x) = 900/300 = 3

  x = arctan(3) ≈ 71.6°

Megan's angle of elevation is about 71.6°.

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wariber [46]

Answer:

I don't know if i'm right but I think it's b.

Step-by-step explanation:

I am so sorry if I am wrong.

7 0
3 years ago
G(x)=2x -3<br> What is the value of<br> G(2) - g(3)
Stells [14]

Answer:

-2

Step-by-step explanation:

You plug the values in. 2(2)-3=1, and 2(3)-3=3

1-3=-2

Hope I helped!

8 0
2 years ago
The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model
Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$  in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

                    $=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

                   $=10,000[e^{0.4}-1]$

                    $=10,000[0.49]$

                    =4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

   $=10,000e^{0.02(5)}$

   $=11051$

In 2000,

$P=10,000e^{0.02(10)}$

   =12,214

Therefore, the change in the population between 1995 and 2000 = 1,163.

8 0
3 years ago
What is 7/10 divided by 2
vodka [1.7K]

Answer:

7/20

Step-by-step explanation:

7/10 ÷ 2/1 is the same as 7/10 * 1/2 which is 7/20

3 0
3 years ago
Karen has calls has 500 or 900 yards of thick soft wool, she has 200 feet at the strore they have 500 feet of wool. How many bal
Flauer [41]

Answer:

Yes.

Step-by-step explanation:

Because yes.

5 0
3 years ago
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