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VashaNatasha [74]
3 years ago
15

Simplify the quotient

title="\sqrt{\frac{5}{2\sqrt{7} } }" alt="\sqrt{\frac{5}{2\sqrt{7} } }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
agasfer [191]3 years ago
8 0
Exact Form (square root of 7 is inside square root of 70 and it is all over 14):
√70√7
————-
14
Decimal Form:
0.97206542...
Lelu [443]3 years ago
8 0

Answer:

14

Decimal Form -0.97206542

Step-by-step explanation:

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Find the common difference of the sequence shown.
larisa86 [58]

Answer:

1/6

Step-by-step explanation:

3 0
3 years ago
The data given to the right includes data from 30 ​candies, and 5 of them are red. The company that makes the candy claims that
lina2011 [118]
100% expansión explanation
4 0
3 years ago
Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a  = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

4 0
3 years ago
Gertie ran 3/4 mile during physical education class. Sarah ran 2/4 mile during the same class. How much farther did Gertie run t
Marizza181 [45]
Gertie   3/4 mile.

Sarah    2/4 mile.

Gertie ran farther by:   3/4  -  2/4  =  (3 -2)/4  = 1/4

Gertie ran farther by 1/4 mile.

6 0
3 years ago
Read 2 more answers
Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra
forsale [732]

Answer:

Quadrant\ IV = (5, -3)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Step-by-step explanation:

Given

Quadrant\ IV = (5, -3)

Quadrant\ II  = (-4, -8)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

Quadrant\ IV = (5, -3)  is correct

Quadrant\ I = (9, 11) is correct

Quadrant\ II = (-1, 3) is correct

Quadrant\ III = (-2, -4) is correct

Quadrant\ II  = (-4, -8) is incorrect

3 0
3 years ago
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