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VashaNatasha [74]
3 years ago
15

Simplify the quotient

title="\sqrt{\frac{5}{2\sqrt{7} } }" alt="\sqrt{\frac{5}{2\sqrt{7} } }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
agasfer [191]3 years ago
8 0
Exact Form (square root of 7 is inside square root of 70 and it is all over 14):
√70√7
————-
14
Decimal Form:
0.97206542...
Lelu [443]3 years ago
8 0

Answer:

14

Decimal Form -0.97206542

Step-by-step explanation:

You might be interested in
Jerome finds out that (3×6) and 18÷2 areequal<br> Explaim why this is true.
ASHA 777 [7]
Because 3*6= 18 and 18/2 equals 9. So therefore they are NOT equal.
5 0
3 years ago
Read 2 more answers
If a globe rotates 150 degrees in 5 seconds, how many rotations does it make in 30 seconds? I got 900 seconds for my answer am I
Maksim231197 [3]

Start with a proportion, to get the number of degrees in 30 seconds:

         (150 degrees / 5 seconds) = ('D' degrees / 30 seconds) .

Cross multiply the proportion:  (150 x 30) = 5 x D

                                                     4,500  =  5 x D

Divide each side by  5 :                  900 = D

The globe turns 900 degrees in 30 seconds.

How many rotations is that ?
Each rotation is 360 degrees.
So 900 degrees is
                               (900 / 360) = <em>2.5 rotations</em> in 30 seconds.


8 0
3 years ago
Between the cows and the chickens , there are 16 eyes and 26 feet. How many chickens does she have and how many cows?
Natalka [10]

Answer:

Step-by-step explanation:

Looks like a system of equation type situation.  To figure it out you wan to set up equations for each thing we know, so eyes and feet.  First you want to make sure you have how many eyes and feet cows and chickens have.    of course they each have 2 eyes while cows have 4 feet and chickens have 2.  Now we can set up the equations.

Let's start with eyes.  16 total and cows will contribute 2 each and chickens will as well.  Another way to write this is 16 = 2o + 2h, where o represents the number of cows and h represents the number of chickens.  If this doesn't make sense maybe plugging in some values to see how it all works.  if there are 3 cows and 4 chickens how many eyes are there?  2*3 + 2*4 = 14, so 14 eyes total.

Similarly for feet we can set up 4o+2h and if you plug in however many cows and chicens there are you'd get the number of legs.  and the problem tells us this equals 26, so 4o+2h = 26

Now the math part, using both equations  we can solve for o and i.

2o+2h=16

4o+2h=26

THere are a few ways to do this.  if you treat o and h like x and y, you could graph both equations and see where they intersect.  Doing this you could make either variable x, so then the other would be y, but you have to make sure all os become the same one and all hs do as well.  

I think it would be easier in general to make one equation equal one of the variables, then replace it in the other equation.  I will show you this method.  First, I want to take the first equation and set it equal to o.

2o+2h=16 divide it by 2

o + h = 8 we want o by itself so subtract h from both sides

o = 8 - h and there we go.

Now we want to replace o in the other equation with this.

4o+2h=26 replace o with 16-h

4(8-h) + 2h = 26  Now just solve for h

32 - 4h + 2h = 26

-2h = -6

h = 3

Now we plug THIS back into the first one.  

o = 8 - h

o = 8 - 3

o = 5

And that should solve it.  with 5 cows and 3 chickens how many eyes and feet are there?

16 eyes and 26 feet, which is exactly what we want.  

Do keep in mind this won't always work, sometimes there is no answer, or every answer works.  You will be able tot ell through this process though.  

3 0
3 years ago
Use the graphs below to find the slope of each line<br><br> (0,8),(8,1)
nignag [31]

Answer:

slope= -7/8

Step-by-step explanation:

y2-y1=1-8=-7

x2-x1=8-0=8

-7/8

6 0
3 years ago
The random variable X has the following probability density function: fX(x) = ( xe−x , if x &gt; 0 0, otherwise. (a) Find the mo
dusya [7]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

\to f_X (x) \ \ xe^{-x} \ , \ x>0

For point a:

Moment generating function of X=?

Using formula:

\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx

M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx

integrating the values by parts:

u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0}  -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\  

        = \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\

Therefore, the moment value generating by the function is =\frac{1}{(t-1)^2}

In point b:

E(X^n)=?

Using formula: E(X^n)= M^{n}_{X}(0)

form point (a):

\to M_{X}(t)=\frac{1}{(t-1)^2}

Differentiating the value with respect of t

M'_{X}(t)=\frac{-2}{(t-1)^3}

when t=0

M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\

M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\

7 0
2 years ago
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