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LenKa [72]
3 years ago
7

Which counterexample shows that the conjecture "Every parallelogram is also a rectangle" is false?

Mathematics
2 answers:
saveliy_v [14]3 years ago
5 0
A parallelogram without four right angles would prove that to be false.
kkurt [141]3 years ago
4 0
Yep that'd be false since they are also rectangles
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A hexagonal prism has a base with an area of 15 square inches and the volume is 105 cubic inches.
Lina20 [59]

Answer:

The height is 7 inches

Step-by-step explanation:

Given

Base\ Area = 15in^2

Volume = 105in^3

Required

Determine the height [missing from the question]

The volume of a hexagonal prism is:

Volume =  Base\ Area * Height

Make Height the subject

Height = \frac{Volume}{Base\ Area}

Height = \frac{105in^3}{15in^2}

Height = \frac{105in}{15}

Height = 7in

4 0
3 years ago
Calculate the number of subsets and the number of proper subsets for the set.
arlik [135]

A set of n elements has 2ⁿ subsets. One of these subsets is the set itself, so this set would have 2ⁿ - 1 <em>proper</em> subsets.

The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

• subsets of size 0 (1 of these):

{ } (empty set)

• subsets of size 1 (4 of these):

{1/6}, {1/7}, {1/8}, {1/9}

• subsets of size 2 (6 of these):

{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

{1/6, 1/7, 1/8}, {1/6, 1/7, 1/9}, {1/6, 1/8, 1/9}, {1/7, 1/8, 1/9}

• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

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A table is on sale for 28% off. The sale price is $414. What is the regular price?
ycow [4]

Answer:

it would be 298.08

Step-by-step explanation:

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bixtya [17]

Answer:

1/16

Step-by-step explanation:

........ .. .............

6 0
4 years ago
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Find each value of x and y
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X is 120 degrees, you ask to find the value of y, but there is no y
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3 years ago
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