Which counterexample shows that the conjecture "Every parallelogram is also a rectangle" is false?
2 answers:
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Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.
