Two positive integers have gcd (a, b) = 15 and lcm (a, b) = 90. Those two numbers are 15 and 90 or 30 and 45.
Suppose we have 2 positive integers, a and b, then:
gcd (a, b) = the greatest common divisor = common prime factors of a and b
lcm (a, b) = the least common multiple = multiplication of the greatest common prime factors of a and b
In the given problem:
gcd (a, b) = 15
prime factorization of 15:
15 = 3 x 5
Hence,
a = 3 x 5 x ....
b = 3 x 5 x ....
lcm (a, b) = 90
prime factorization of 90:
90 = 3 x 5 x 2 x 3
Therefore the possible pairs of a and b are:
Combination 1:
a = 3 x 5 = 15
b = 3 x 5 x 2 x 3 = 90
Combination 2:
a = 3 x 5 x 2 = 30
b = 3 x 5 x 3 = 35
We can conclude the two integers are 15 and 90 or 30 and 45.
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Answer: 3
Step-by-step explanation:
Volume = pir2h/3
Answer:
n=5
Step-by-step explanation:
6(n-2)-8=22+4(2-n)
open brackets
6n-12-8=22+8-4n
collect like terms
6n+4n=22+8+12+8
10n=50
n=50/10
n=5
8.75 x 10 = 87.50, easiest way to figure out is divide each amount by each answer choice
Answer:
How to be more efficient and how to pay for a project.
Hope it helps!
Step-by-step explanation:
