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3 years ago

Answer choices are

Mathematics

2 answers:

lana66690 [7]3 years ago

7 0

Answer:

C IS YO ANSWERRRR BOII

Step-by-step explanation:

V125BC [204]3 years ago

3 0

8.75 x 10 = 87.50, easiest way to figure out is divide each amount by each answer choice

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A swimming pool measures 35 feet wide by 50 feet long. What is the ratio of the length to the perimeter in simplest form?

seropon [69]

Answer:

i think it is 5:17

Step-by-step explanation:

length=50

perimeter=170

the highest factor of 50 and 170 is 10 so the answer will be 5:17

hopefully this made sense

6 0

3 years ago

HELLLLLPPPPPPPPPP WITH THESE QUESTIONS

vredina [299]

What questions? Idk where the pic is

3 0

3 years ago

Which of the following numbers is irrational? -9/5 , sqrt (5) , 7/3 , sqrt (9)

kirza4 [7]

Sqrt 5 because it’s an imperfect square. Fractions with integers are always rational and sqrt 9 is perfect so it is also an integer.

8 0

3 years ago

Read 2 more answers

2. Fran needs a bookcase to hold all of his math books. He decides to try to build the bookcasepictured below. He needs to buy t

astraxan [27]

Let's rewrite the mixed number as a fractions:

$\begin{gathered} 3\frac{2}{3}=\frac{11}{3} \\ 4\frac{1}{2}=\frac{9}{2} \end{gathered}$

Therefore, the total length will be:

$3\cdot(\frac{11}{3})+2(\frac{9}{2})+4=24ft$

5 0

11 months ago

A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3

Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = $nPk=\frac{n!}{(n-k)!}$

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = $5P4+4P2+8P3$

$=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468$

So, this can be done in 468 ways.

7 0

3 years ago