Answer:
- max for 5th-degree: 4 turns. This function: 2 turns.
- max for 7th-degree: 6 turns. This function: 0 turns.
Step-by-step explanation:
In general, the graph of an n-th degree function can make n-1 turns. However, in specific cases, the number of turns is limited by the number of real zero-crossings of the derivative.
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1. This 5th-degree function can have at most 4 turns. However, the derivative, f'(x) = 5x^4 -3, has only two (2) real zeros. Hence the graph of this function can only have 2 turns.
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2. This 7th-degree function can have at most 6 turns. However, the derivative, f'(x) = -7x^6 -35x^4-12x^2, has an even-multiplicity root at x=0 only. The derivative never crosses 0. Hence the graph makes no turns.
Answer:
so the first one i think is 1 and the second one is 4
Step-by-step explanation:
Notice that the line with negative slope has a y-intercept of 5 and the line with positive slope has a y-intercept of 2.
On the other hand, the slope of the line with negative slope is -2, while the slope of the line with positive slope is 3 (This can be identified since in one case, the value of y decreases by 2 for each increase of 1 unit in x, and in the other, the value of y increases by 3 for each increase of 1 unit in x).
Using the y-intercept form to represent each line, the system of equations represented by the graph must be equivalent to:

From the given options, the one that displays the correct system of equations is option A.
Therefore, the answer is:
The inequality would start out looking like this:

Now it's just a matter of solving the inequalities simultaneously. Get rid of the fraction by multiplying everything by 9:

Then distribute the 5 into the parenthesis:

Now add 160 everywhere:

and finally divide everything by 5:
-22<F<266