Let x = Darlene's dog's weightlet y = Leah's dog's weight x = 5yx + y = 84 so, 5y + y = 84, which means 6y = 84 so, y = 84/6 = 14x = 5(14) = 70 Darlene's dog = 70 lbs, Leah's dog = 14 lbs.

4 0

3 years ago

Almost all companies utilize some type of year-end performance review for their employees. Human Resource (HR) at a university's

balu736 [363]

Answer:

The Answer is 76.

Step-by-step explanation:

Given the normal distribution " 10% of employees (rated) exemplary, 20% distinguished, 40% competent, 20% marginal, and 10% unacceptable'', we can see that exemplary employees are top 10% rated employees.

We have the formula for normal distribution:

z=(X-M)÷σ

where z is the minimum z-score for top 10% employee, X is the minimum score for top 10% employee, M is the mean of the score distribution, σ is the standard deviation of the score distribution.

The z-score we are looking for is the value "a" that separates the highest 10% from the lowest 90% i.e. P(z≤a)=0.90

If we look at z-table, corresponding value for a is 1.28155

We can now put the values in the formula:

1.28155= $\frac{X-50}{20}$

So X=(1.28155×20)+50=75.631

Therefore minimum score for exemplary employee is 76.

3 0

2 years ago