0.99 is the answer it greater than 0.1
Answer:
y'(t)=ky(t)(100-y(t))
Step-by-step explanation:
The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)
If y(t) is the percent of the population advocating war at time t
then 100-y(t) is the percent of the population not advocating war
The product of the percentage of the population advocating war and the percentage not advocating war would be
y(t)(100-y(t))
If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then
y'(t)=ky(t)(100-y(t))
where <em>k is the constant of proportionality
</em>
Answer:
42.78⁹, 137.22⁹.
Step-by-step explanation:
sine Ф=0.6792
Angle Ф in the first quadrant = 42.78 degrees.
The sine is also positive in the second quadrant so the second solutio is
180 - 42.78
= 137.33 degres.
I think it's <span>121212121/100000000 but I'm not sure...
</span>
Answer:
0.20p + 7 = 0.30p + 5
Step-by-step explanation:
- I
- took
- the
- test
- Enjoy!
- UwU
