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nignag [31]
2 years ago
7

What is 17/20 - 4/15

Mathematics
1 answer:
Zinaida [17]2 years ago
4 0

Hello there, today you gave us the problem \frac{17}{20}-\frac{4}{15},

Our first step is to give them common denominators, which is \frac{51}{60}-\frac{16}{60}, solve it and we get \frac{35}{60} as our answer, which can be simplified down to \frac{7}{12}

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Which pair of monomials has the least common multiple (LCM) of 54x2y3?
Lera25 [3.4K]

ANSWER

The correct answer is D.

EXPLANATION

If we express the monomial,

18 {x}^{2} y

as product of primes, we obtain:

2 \times  {3}^{2}  \times  {x}^{2}y

If we express the monomial

27x {y}^{3}

as product of primes we obtain:

=  {3}^{3}  \times x {y}^{3}

The least common multiple of these two binomials is the product of the highest powers of the common factors.

The LCM is

= 2 \times  {3}^{3}  \times  {x}^{2} {y}^{3}

=54 {x}^{2} {y}^{3}

Therefore the correct answer is D.

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3 years ago
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I don’t understand the equation but you can use Photomath to solve any equation you need to solve. It’s and app for free.
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3 years ago
Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)
ELEN [110]

Question:

Find the point (,) on the curve y = \sqrt x that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

Step-by-step explanation:

y = \sqrt x can be represented as: (x,y)

Substitute \sqrt x for y

(x,y) = (x,\sqrt x)

So, next:

Calculate the distance between (x,\sqrt x) and (3,0)

Distance is calculated as:

d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}

So:

d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}

d = \sqrt{(x-3)^2 + (\sqrt x)^2}

Evaluate all exponents

d = \sqrt{x^2 - 6x +9 + x}

Rewrite as:

d = \sqrt{x^2 + x- 6x +9 }

d = \sqrt{x^2 - 5x +9 }

Differentiate using chain rule:

Let

u = x^2 - 5x +9

\frac{du}{dx} = 2x - 5

So:

d = \sqrt u

d = u^\frac{1}{2}

\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}

Chain Rule:

d' = \frac{du}{dx} * \frac{dd}{du}

d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}

d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}

d' = \frac{2x - 5}{2\sqrt u}

Substitute: u = x^2 - 5x +9

d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}

Next, is to minimize (by equating d' to 0)

\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0

Cross Multiply

2x - 5 = 0

Solve for x

2x  =5

x = \frac{5}{2}

Substitute x = \frac{5}{2} in y = \sqrt x

y = \sqrt{\frac{5}{2}}

Split

y = \frac{\sqrt 5}{\sqrt 2}

Rationalize

y = \frac{\sqrt 5}{\sqrt 2} *  \frac{\sqrt 2}{\sqrt 2}

y = \frac{\sqrt {10}}{\sqrt 4}

y = \frac{\sqrt {10}}{2}

Hence:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

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The diameter is twice as big as the radius

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What is the pattern and the 2 next numbers of 7, 14, 8, 16, 10, 20, 14,
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Answer:

Next 2 numbers are 28,22

Step-by-step explanation:

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