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Illusion [34]
3 years ago
13

F(x) = (x-3) (x+8) (x-11) What are the zeros of the polynomial?

Mathematics
1 answer:
aalyn [17]3 years ago
6 0
<span>hello :
</span>F(x) = (x-3) (x+8) (x-11)
F(x) =0
<span>x-3= 0 or x+8=0 or x-11 = 0
x=3 or x=-8 or x=11
</span><span>the zeros of the polynomialare : 3   , -8   , 11 </span><span>
</span>
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Answer:

w = 6

Step-by-step explanation:

ST = w + 6,

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From the diagram given, we can deduce that PR is the midsegment of ∆QST. Therefore, according to the midsegment theorem:

PR = ½ of ST

Plug in the values into the equation and solve for w.

w = \frac{1}{2}(w + 6)

w = \frac{w}{2} + 3 (distributive property of equality)

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2(w - 3) = \frac{w}{2}*2 (multiplication property of equality)

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Divide both sides by -1

6 = w

w = 6

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Answer:

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