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Anuta_ua [19.1K]
3 years ago
6

Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models

the cost x, in dollars, of a ticket? A.|5x+4|<80 B.|5x-4|<80 C.|80-5x|<4 D.|80+5x|<4
Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

Option C \left|80-5x\right|\le 4

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above  $80

so

5x\leq 80+4

Solve for x

x\leq \$16.80

The total cost to be no more than $4  below $80

so

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2

therefore

The inequality that represent this problem is

\left|5x-80\right|\le 4

<u><em>Verify</em></u>

<em>First solution (positive case</em>)

+(5x-80)\le 4

5x\le 80+4

Solve for x

x\leq \$16.80 ----> is ok

<em>Second solution (negative case)</em>

-(5x-80)\le 4

Multiply by -1 both sides

(5x-80)\ge -4

5x\geq 80-4

Solve for x

5x\geq 76

x\geq \$15.2 ---> is ok

Remember that

\left|5x-80\right|\le 4 is equivalent to \left|80-5x\right|\le 4

Because is a absolute value

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2 years ago
Solve. State the number of solutions.
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Answer:

a. x=8

b.Step 1: Simplify both sides of the equation.

2(2x−2)=4x−4

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4x−4=4x−4

Step 2: Subtract 4x from both sides.

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Answer:

All real numbers are solutions.

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3(x+1)=4x+7−x

(3)(x)+(3)(1)=4x+7+−x(Distribute)

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3x+3=3x+7

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2 years ago
A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th
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Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

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The critical value of <em>z</em> for 95% confidence level is,

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Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

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Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

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