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Darina [25.2K]
2 years ago
7

Nona is building a rectangular patio extending outside her house, so one edge of the patio is along the wall of the house. The a

rea of her patio is going to be 72 ft. She has 26 feet of fencing available to fence in the three sides of the house that are not against the wall. What are the two possible sets of dimensions for the patio?
Mathematics
1 answer:
pashok25 [27]2 years ago
4 0
The 2 possible ways to fence in the patio are having 8x9, with the nine being the length of the wall. Because 8+8+9=26. The second way is 18x4 and the 18 being the length of the wall. Because 18+4+4=26.
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Answer:

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Step-by-step explanation:

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3 years ago
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Vinil7 [7]

Answer:

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Step-by-step explanation:

Arithmetic sequence:

       \sf \boxed{t_n=a+(n-1)d}

Here a is the first term and d is the common difference.

      t_{14}= 6    ⇒  \sf a + 13 d = 46  ------------(I)

     \sf t_{20} = 100 ⇒   a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1)    a + 19d = 100

(II)    a + 13d   =  46

      <u>-    -            -</u>

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                 \sf \boxed{d = 9}

Substitute d = 9 in equation(I) and find 'a',

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\sf t_3 = -71 + 2*9

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\sf t_n= -71 + (n-1)*9

    = -71 + 9*n - 1 *9

    = -71 + 9n - 9

    = -71 - 9 + 9n

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5 0
1 year ago
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USPshnik [31]
I hope this helps you

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2 years ago
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Step-by-step explanation:

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