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Darina [25.2K]
3 years ago
7

Nona is building a rectangular patio extending outside her house, so one edge of the patio is along the wall of the house. The a

rea of her patio is going to be 72 ft. She has 26 feet of fencing available to fence in the three sides of the house that are not against the wall. What are the two possible sets of dimensions for the patio?
Mathematics
1 answer:
pashok25 [27]3 years ago
4 0
The 2 possible ways to fence in the patio are having 8x9, with the nine being the length of the wall. Because 8+8+9=26. The second way is 18x4 and the 18 being the length of the wall. Because 18+4+4=26.
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zvonat [6]
Let present ages of father be x and of son is y years

x/y  = 7/2, 2x=7y, y=2x/7
(y+5)=37/100*(x+5)
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(2x+35)/7=(37x+185)/100
200x+3500=259x+1295
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8 0
3 years ago
A given rectangle has an area of 20 ft.² what is the length for various widths
ruslelena [56]
The area of a rectangle is calculated as length times its width. So, for the given area above, the expression should b written as:

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L = 20 / W

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3 years ago
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7 0
3 years ago
Y=8x-4 find y and x intercept
dlinn [17]

Answer:

<h3>The x intercept is 1/2</h3><h3>The y intercept is - 4</h3>

Step-by-step explanation:

y = 8x - 4

First to find the y intercept let x = 0

Substitute the value of x into the equation

That's

y = 8(0) - 4

y = - 4

<h3>The y intercept is - 4</h3>

To find the x intercept let y = 0

Substitute the value of y into the equation

that's

8x - 4 = 0

8x = 4

Divide both sides by 8

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Hope this helps you

5 0
4 years ago
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answer

</span><span>A. about $25.30</span>
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4 years ago
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