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Furkat [3]
3 years ago
15

Help me please as soon as possible

Mathematics
2 answers:
Stella [2.4K]3 years ago
6 0
90+31= 121
3x-1+121=120
3x+120=180
-120
3x=60
Divide by 3 on both sides
X=20
Nookie1986 [14]3 years ago
4 0
X=15


90+31+3x-1=180
121+3x-1=180
120+3x=180
3x=60
X=15
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Salina, Tamara, and Uma are working on their homework together. Salina tells her friends that she got θ=52∘θ=52∘ for the inverse
svlad2 [7]

Answer:

The values reported by Uma, Salina, and Tamara are all possible values for inverse cosine

Step-by-step explanation:

Solution:-

- The solution to the inverse "cosine" problem would have a general form:

                                    θ = cos^-1 ( a )

Where,  a: Any arbitrary constant, - 1 < a < 1

- The value of θ = 52° was reported by Salina suggests that the answer lies in the first quadrant of a cartesian plane where ( sin (θ) , cos (θ) , tan (θ) ) have positive values for "a".

Hence,                            0 < a < 1 , θ = 52°

- The value of θ = 128° was reported by Tamara suggests that the answer lies in the second quadrant of a cartesian plane where ( sin (θ) ) have positive values for "a" and (cos (θ) , tan (θ) have negative values for "a". So for cos (128):

Hence,                           -1 < a < 0 , θ = 128°

- The value of θ = 308° was reported by Uma suggests that the answer lies in the fourth quadrant of a cartesian plane where ( cos (θ) ) have positive values for "a" and (sin (θ) , tan (θ) have negative values for "a". So for cos (308):

Hence,                           0 < a < 1 , θ = 308°

- The angle θ reported by Uma and Salina are similar solution because of property law of complementary angles:

                                     cos (θ) = cos ( 360 - θ )

Where, θ = 52°,            cos (52°) = cos( 308°)  .. Uma and Salina conform

However,                      cos ( 180 - θ ) = - cos (θ)  

                                     cos(128) = - cos ( 52 ) .... Uma and Tamara conform.

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3 years ago
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melamori03 [73]

Answer:

Its D thats the answer

Step-by-step explanation:

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This is false because \sqrt{2} is an irrational number, despite being between 1 and 2.

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