Select the correct symbol

Mathematics

2 answers:

astraxan [27]3 years ago

6 0

Answer:

Step-by-step explanation:

$\sqrt{33} =5.74...\\\frac{16}{3} =5.33...$

KIM [24]3 years ago

4 0

Answer:

a is the correct answer let me know

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PLEASE HELP ASAP!!!

Sonbull [250]

2x^2 - 7x - 6 = 0

$x1 = \frac{- b + \sqrt{ {b}^{2} - 4ac }}{2a}$
$x2 = \frac{- b - \sqrt{ {b}^{2} - 4ac }}{2a}$
where a=2
where b=-7
where c=-6

solve for x1 and x2

x1=4.21
x2=-0.71

6 0

3 years ago

What type of angle is this

DaniilM [7]

Obtuse angle that’s the answer

7 0

3 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$