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notka56 [123]
3 years ago
12

Suppose I send an email with the following characteristics: 25% open rate; 5% click-through rate (calculated from total delivere

d emails); 20% conversion rate; $100 average order value. How much revenue can I expect this email to generate if I send it out to my entire email list of 1000 members?
Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

$250

Step-by-step explanation:

Email Open rate = 25%

Email click through rate = 5%

Conversion rate = 20%

Average order value = $100

Combining these factors together, total expected conversion per email:

Open rate * Click through rate * Conversion rate * average order value

= 0.25 * 0.05 * 0.20 * 100 = $0.25

Email list consists of 1000 members. So the total revenue expected = $0.25 * 1000 = $250

In other words, sending the email to entire email list is expected to generate $250.

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Roberto is having his house painted. The job takes three days, and he pays the painter the same hourly rate everyday. The cost o
Gelneren [198K]

Answer:

a is the answer

Step-by-step explanation:

4 0
3 years ago
Find the sum of those four-digit numbers which contain the digits 2,4,5,9 (and the digits are not repeated).
LekaFEV [45]

Answer:

Sum of all 4 digits number which contains 2,4,5,9(without repetition) = 133320

Step-by-step explanation:

Let suppose sum of All 4 digits number which contains 2,4,5,9(without repetition) is A×10^{3} +B×10^{2} +C×10 + D(equation 1)

if we fix 2 at unit place ( _ , _ , _ , 2)  then total  no of possible outcomes is 3!(3×2×1)

and sum of all possible outcomes of which has 2 at unit place is 3!×2

Similarly,

if we fix 4 at unit place then we got sum 3!×4

if we fix 5 at unit place then we got sum 3!×5

if we fix 9 at unit place then we got sum 3!×9

So,  the total sum  of unit place will be  3!×20

D = 3!×20

In the same above manner we will do for ten's place then we got result

C = 3!×20

In the same above manner we will do for Hundred's place then we got result

B = 3!×20

In the same above manner we will do for Thousand's place then we got result

A = 3!×20

Then,  Replace A,B,C & D in equation 1

we got new equation =  3!×20×10^{3} +3!×20×10^{2} +3!×20×10 + 3!×20

lets take  3!×20 common

3!×20(1+10^{1}+10^{2}+10^{3} )

if we observe then it is a Geometric Progression

Sum of "n" number of Geometric Progression is = \frac{a_{1}(r^{n}-1 )}{r-1}

a_{1} = the first term

r = common ratio

n = number of terms

In above case,

a_{1}  = 1

r = 10

n = 4

hence,\frac{1(10^{4}-1 )}{10-1} = \frac{9999}{9} = 1111

Sum of all 4 digits number which contains 2,4,5,9(without repetition) = 3!×20×111

=133320

6 0
3 years ago
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nikklg [1K]

Answer:

help with what?

you don't have a question.

Step-by-step explanation:

3 0
3 years ago
the scale from a square park to a drawing is 5 m to 1 cm .the actual park has an area of 1600 m2 .what is the area of the drawin
lawyer [7]

The area of the drawing of the park is 64 cm²;

Scale: Square park to Drawing = 5m:1cm

                                                 = 5m:0.01m;

Therefore; Square Park Area = 1600m²;

                 Drawing Area = 1600 ×(0.01/5)²

                                        = 0.0064m² = 64 cm²

To learn more about this; visit: brainly.com/question/22797576

#SPJ9

7 0
1 year ago
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Law Incorporation [45]
Hey there Rosy! I did this recently and the answer is:

1 : 4

2 to 8

18
---
72
7 0
4 years ago
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