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3 years ago

How many 3/8’s are in 6

Mathematics

1 answer:

Agata [3.3K]3 years ago

8 0

$\huge\mathfrak\pink{Answer}$

there are 16 3/8s in 6

$\huge\mathcal\green{hope \: this \:may }\huge\mathcal\pink{be \: helpful}$

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(Re-Asking This Question, NO scam answers or LINKS. I will report.)

AlexFokin [52]

Answer:

Yes

Step-by-step explanation:

This is because the first point in the parenthesis is x and the second is y. If we know this, we can substitute -5 in for x and -6 in for y to get that -15 - (-12) > -4. When you subtract by a negative number, it is the same as adding by that number, so -15 - (-12) = -15 + 12, so we get that -3 > -4. This is true because when you have negative numbers, the lesser negative number is the greater one (Ex. -5 > -6).

3 0

3 years ago

Using the tree diagram what is the probability that a player will reach Level 2 with the bonus?

pentagon [3]

That is 0.3*0.3*0.3 = 0.027

6 0

3 years ago

Eight more than three times the difference of four and a number” when n = 3?

Snezhnost [94]

8 + 3 (4 - n )
n= 3
8 + 3( 4-3)
8 + 3 * 1
8 + 3 = 11

8 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago

Helllp geometry! Pls!

creativ13 [48]

He should use the Pythagorean Theorem to find the missing length.

Since KT is tangent to the circle and TL reaches the center of circle L, the measure of angle LTK is 90 degrees. This means that triangle LTK is a right triangle which means the Pythagorean Theorem can be used.

So,
TL²+(12)²=(13)²
=> TL²+144=169
=> TL²=25
=> TL = 5

Therefore, the radius of circle L is 5 feet.

7 0

3 years ago