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MrRissso [65]
2 years ago
7

PLeAsE HeLp Me (Both images are supposed to be together)

Mathematics
1 answer:
Soloha48 [4]2 years ago
5 0

Answer:

No, the slope of Tiana's representation is not equal to the other slopes.

Step-by-step explanation:

The slopes aren't the same as the words and the table.

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What is the solution?
BaLLatris [955]

Answer:

What's the question?

Step-by-step explanation:

I hope you have a good night btw!!!

4 0
2 years ago
Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro
puteri [66]

Answer:

(a) P(0 ≤ Z ≤ 2.87)=0.498

(b) P(0 ≤ Z ≤ 2)=0.477

(c) P(−2.20 ≤ Z ≤ 0)=0.486

(d) P(−2.20 ≤ Z ≤ 2.20)=0.972

(e) P(Z ≤ 1.01)=0.844

(f) P(−1.95 ≤ Z)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)=0.862

(h) P(1.01 ≤ Z ≤ 2.50)=0.150

(i) P(1.20 ≤ Z)=0.115

(j) P(|Z| ≤ 2.50)=0.988

Step-by-step explanation:

(a) P(0 ≤ Z ≤ 2.87)

In this case, this is equal to the difference between P(z<2.87) and P(z<0). The last term is substracting because is the area under the curve that is included in P(z<2.87) but does not correspond because the other condition is that z>0.

P(0 \leq z \leq 2.87)= P(z

(b) P(0 ≤ Z ≤ 2)

This is the same case as point a.

P(0 \leq z \leq 2)= P(z

(c) P(−2.20 ≤ Z ≤ 0)

This is the same case as point a.

P(-2.2 \leq z \leq 0)= P(z

(d) P(−2.20 ≤ Z ≤ 2.20)

This is the same case as point a.

P(-2.2 \leq z \leq 2.2)= P(z

(e) P(Z ≤ 1.01)

This can be calculated simply as the area under the curve for z from -infinity to z=1.01.

P(z\leq1.01)=0.844

(f) P(−1.95 ≤ Z)

This is best expressed as P(z≥-1.95), and is calculated as the area under the curve that goes from z=-1.95 to infininity.

It also can be calculated, thanks to the symmetry in z=0 of the standard normal distribution, as P(z≥-1.95)=P(z≤1.95).

P(z\geq -1.95)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)

This is the same case as point a.

P(-1.20 \leq z \leq 2.00)= P(z

(h) P(1.01 ≤ Z ≤ 2.50)

This is the same case as point a.

P(1.01 \leq z \leq 2.50)= P(z

(i) P(1.20 ≤ Z)

This is the same case as point f.

P(z\geq 1.20)=0.115

(j) P(|Z| ≤ 2.50)

In this case, the z is expressed in absolute value. If z is positive, it has to be under 2.5. If z is negative, it means it has to be over -2.5. So this probability is translated to P|Z| < 2.50)=P(-2.5<z<2.5) and then solved from there like in point a.

P(|z|

7 0
3 years ago
Read 2 more answers
In ΔCDE, the measure of ∠E=90°, the measure of ∠D=23°, and EC = 1.3 feet. Find the length of DE to the nearest tenth of a foot.
BabaBlast [244]

Answer: length of DE is about 3.3 ft

Step-by-step explanation:  A calculator is necessary!

DE is the unknown hypotenuse of the triangle

get the sine of 23° = 0.3907311285

Use the equation for sine

<em>sin = o/h</em> .

To find h,  Substitute values for sin and o.  O is EC, Opposite the 23° angle D

<em>0.3907311285 = 1.3/h</em> multiply both sides by h

h(0.3907311285) = 1.3 divide both sides by 0.3907311285

h = 1.3/0.3907311285

3.327096065 = h, the length of the hypotenuse, DE.

7 0
2 years ago
Zoom in to see the question plzzz help!!!
kondor19780726 [428]

Answer:

\huge\boxed{\boxed{IV}}

Step-by-step explanation:

Given:

x>0

Which means

x is any number greater than 0 ig 1,2,3,4,5,7,9.......

y<0

Which means

y Is any number smaller than 0

ig -1,-2,-3,-4,-5.........

So according to the question

The coordinates are

(x,-y)

Therefore,

The points are located to Quadrant IV

6 0
3 years ago
Use function notation that describes the value of the function m at x
mr_godi [17]

Answer:

A function is a relation in which each possible input value leads to exactly one output value. We say “the output is a function of the input.”

The input values make up the domain, and the output values make up the range.

Step-by-step explanation:

5 0
3 years ago
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